Very similar questions were asked before in the discourse (see e.g. this , this , and this ). Answers point to MathLink where one can plug an expression like this using MathLink sqx = W`Sqrt[x]` and then evaluate this function like so weval(sqx; x=2.0) # 1.4142135623730951 I would like to define a …

For completeness, the answer I was looking for was given in this post and this is the solution (for more details read the thread in the other post). using SymPy const sympy_parsing_mathematica = SymPy.PyCall.pyimport("sympy.parsing.mathematica") s = "(Sqrt[Pi])/(2*EllipticE[m])" ex = sympy_parsing…

How to copy Mathematica expression into a Julia function

Specific Domains Modelling & Simulations

stevengj August 8, 2023, 3:54pm 6

See: Best Practices for converting a Mathematica expression to Julia - #3 by stevengj

1 Like

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How to copy Mathematica expression into a Julia function

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