In the following pseudocode, is it possible to drop the foo quote inside the fizzbuzz function? bar = quote foo = quote i = rand() j = 7 end function fizzbuzz() # want foo here k = i * j end end For clarity, the following works with foo defined outside the bar quote: f…

How do you drop one quote inside another?

djsegal May 9, 2020, 11:55am 5

Solid effort, but the real answer I guess was that you have to flip the problem on its head?

The way I got around this situation is copying the work of InteractNext.jl

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