How do I create a function from an expression

General Usage
6

But I think I found a fix

macro expr2fn(fname, expr, args...)
    fn = quote
        function $(esc(fname))()
            $(esc(expr.args[1]))
        end
    end
    for arg in args
        push!(fn.args[2].args[1].args, esc(arg))
    end
    return fn
end

@expr2fn(f, :(sin(x+y)), x, y)

julia> f(1.0, 1.0)
0.9092974268256817

I guess it’s just the documentation is never clear about what I can get if I pass a quoted expression into a macro.