Get the name of the invoking module

[pfitzseb]

Get module of a caller

module A foo(???) = println("I've been called from $???") end module B import A A.foo() # should pring "I've been called from B" end Is it possible to get this behavior, i.e. find out the caller’s module without requiring it to explicitly pass @__MODULE__? I tired: foo(; mod=@__MODULE__) But for obvious reasons it returns the module of foo itself instead of the caller.

But it’s not a good idea to do this. If you want to do something as intrusive as eval’ing code into a module that’s not yours then do at least require that to be explicitly passed.