How can I get a function f, from the type of the function, i.e. typeof(f)? Here’s the full story, to avoid the XY problem: I’m using ChainRulesOverloadGeneration which is giving me typeof(f). I would like to run Base.return_types(f, (Float64,)) and do different overloads based on the answer of this…

Get f from typeof(f)

aramirezreyes June 14, 2022, 4:46am 2

Topic		Replies	Views
How to get a function instance from a function type? Internals & Design type , function	3	759	April 17, 2022
Is there a way to get f from typeof(f)? General Usage	17	4283	December 29, 2018
Getting the return type of a function call without actually running it General Usage	4	711	July 20, 2018
Strange result in typeof of a Function New to Julia	3	587	November 21, 2018
Extract function from function type General Usage type , functions	13	700	November 22, 2022