I assume you want another random vector, can you just re-scale it?
julia> a = rand(1000:2000,5)
5-element Vector{Int64}:
1484
1053
1135
1863
1823
julia> b = rand(1000:2000,10)
10-element Vector{Int64}:
1784
1708
1512
1169
1703
1394
1855
1520
1645
1652
julia> b = b * sum(a)/sum(b)
10-element Vector{Float64}:
823.4018316396939
788.3241751348639
697.8607452013549
539.5497428177142
786.0164345753356
643.3980679964873
856.1717475849956
701.5531300966002
759.2466440848074
762.477480868147
julia> sum(b) ≈ sum(a)
true
julia> sum(b) == sum(a) #I don't think this is always true
true
If you need Integer, I suppose you can just trunc and wiggle a single element value until the sum matches.