I came across this strange behavior: function f(k) if k == 1 g(k) = "k = 1" elseif k == 2 g(k) = "k = 2" end g(k) end f(1) # returns "k = 2" f(2) # errors ERROR: UndefVarError: g not defined What’s going on here? How can I get around this?

[image] Confused by behaviour of nested functions New to Julia Don’t define functions conditionally inside other functions: disallow methods of local functions in different blocks · Issue #15602 · JuliaLang/julia · GitHub . and messages below

Function inside function is not defined?

General Usage

giordano March 2, 2021, 2:53am 2

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Function inside function is not defined?

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