Find zero of a nonlinear equation using Julia

General Usage
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6

my function was written incorrectly, this runs without problem and finds a zero

function R(F,p) #p is a vector too, not a number
F[1] = -5.0488*p[1] + p[1]^2.81 - 3.38/( p[1]^(-1.0) )^2.0
end
nlsolve(R , [5.8])

the results are:

julia> nlsolve(R , [5.8])
Results of Nonlinear Solver Algorithm
 * Algorithm: Trust-region with dogleg and autoscaling
 * Starting Point: [5.8]
 * Zero: [5.934184191445043]
 * Inf-norm of residuals: 0.000000
 * Iterations: 3
 * Convergence: true
   * |x - x'| < 0.0e+00: false
   * |f(x)| < 1.0e-08: true
 * Function Calls (f): 4
 * Jacobian Calls (df/dx): 4
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