I have an array like this a = [ rand(1:20,3) for i in 1:2,j in 1:3] 2×3 Array{Array{Int64,1},2}: 2×3 Array{Array{Int64,1},2}: [8, 13, 1] [12, 4, 9] [13, 18, 7] [3, 19, 20] [8, 3, 11] [10, 9, 12] I would like that for each row, obtain an array 1 x 3 with maximum in each position along the r…

Here are two ways: julia> a = [ [[8, 13, 1]] [[12, 4, 9]] [[13, 18, 7]] [[3, 19, 20]] [[8, 3, 11]] [[10, 9, 12]] ] # as in original question 2×3 Matrix{Vector{Int64}}: [8, 13, 1] [12, 4, 9] [13, 18, 7] [3, 19, 20] [8, 3, 11] [10, 9, 12] julia> [maximum.(b) for b in eachrow(a…

[maximum.(b) for b in eachrow(a)]

Thanks for the answer. If you wish, you can also answer the same question on the stackoverflow: In Julia, Find the maximum for each position of a set of arrays - Stack Overflow I’ll give you the ok on this platform too.

Ok, this one-liner comprehension seems to do the job: [maximum(hcat(b...),dims=2) for b in eachrow(a)]

Find the maximum for each position of a set of arrays

General Usage

maoc May 31, 2021, 10:20pm 3

It gives me the maximum of each elemt. I would like the maximimum by position, for each row.

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Find the maximum for each position of a set of arrays

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