I am trying to do a 2D FFT of an image: using AbstractFFT img=[sin(2*pi*x*10/256) for x in 1:256, y in 1:256]; fft(img) but this gives: julia> fft(img) ERROR: MethodError: no method matching plan_fft(::Matrix{ComplexF64}, ::UnitRange{Int64}) Closest candidates are: plan_fft(::AbstractArray{var"…

The intro of the package: This package is mainly not intended to be used directly. Instead, developers of packages that implement FFTs (such as FFTW.jl or FastTransforms.jl) extend the types/functions defined in AbstractFFTs. This allows multiple FFT packages to co-exist with the same underlying ff…

Fft of Matrix type doesnt work?

New to Julia

rafael.guerra June 14, 2021, 7:14pm 2

Why using AbstractFFT and not just FFTW?
See this post for further leads.

Topic		Replies	Views
I succeeded to 2d FFT of image. But New to Julia	2	3881	March 28, 2019
I didn't ask for plan_bfft, but got MethodError: no method matching plan_bfft(::Vector{Number}, ::UnitRange{Int64}) Signal and Image Processing fftw	3	722	June 16, 2022
Getting different output for fft function in julia and matlab Signal and Image Processing fftw , matlab , matrices	4	2959	June 22, 2021
Why I can't use mul! and plan_fft together? New to Julia question , fftw , bug , linearalgebra	4	1124	January 26, 2022
Plan FFTs both in julia 0.6.3 and 0.7 General Usage fftw	2	1266	June 17, 2018

Fft of Matrix type doesnt work?

Related topics