Hi, In base/float.jl I don’t understand the definition of floor: Here floor(::Type{T}, x::AbstractFloat) where {T<:Integer} = trunc(T,round(x, RoundDown)) I don’t get the round. What I understood is: trunc(.) = round(., RoundDown) but I am probably missing something. Thank you for the help.

[image] remi-garcia: What I understood is: trunc(.) = round(., RoundDown) but I am probably missing something No, trunc uses RoundToZero . julia> floor(-1.4) -2.0 julia> trunc(-1.4) -1.0

Definition of floor

New to Julia

stevengj September 9, 2020, 4:38pm 3

No, trunc uses RoundToZero.

julia> floor(-1.4)
-2.0

julia> trunc(-1.4)
-1.0

3 Likes

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Definition of floor

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