Define f with keyword arguments: function f does not accept keyword arguments

[taqtiqa-mark]

Update:
The following was an artifact of using the same REPL session used to define f(a=1,b=2):

@taqtiqa-mark

After some digging I realized I had thought I was looking at something like this definition:

julia> f(; a=1,b=2)=2a+4b
f (generic function with 3 methods)
julia> f(b=1,a=2)
8

In fact in v1.0.2 using a clean REPL:

julia> f(;a=1,b=2)=2a+4b
f (generic function with 1 method)

julia> f(b=1,a=2)
8

julia> f()
10

For those following along at home…

@klaff and I were not alone….
Some attempt at documenting what the current behavior is…