CUDA.sqrt is GPU only. The following code is OK.
using CUDA
function sqrt_kernel!(res, val)
res[begin] = CUDA.sqrt(val)
return
end
res = cu([0.0])
@cuda sqrt_kernel!(res, 12.34)
println(res[begin])
Answered by
https://github.com/JuliaGPU/CUDA.jl/issues/559#issuecomment-731595826