Hello there, say I want to create a new type which is basically the same of Array{Float64, 1} except for the behaviour for one operator (for example +). What I’m doing now is the following. First create a new mutable type MyVec struct MyVec v::Array{Float64, 1} end and then overloading the oper…

I am kinda surprised nobody mentioned Lazy.jl and its macro @forward . Basically you can do: import Base: length, getindex, setindex using Lazy: @forward struct MyVec <: AbstractVector{Float64} v::Vector{Float64} # same as Array{Float64, 1} end @forward MyVec.v Base.size, Base.getindex, Base.se…

Confused with type definition

New to Julia

sostock January 10, 2021, 3:40pm 10

It does not work (or rather, cannot be printed) because a subtype of AbstractVector must implement some methods, see here.

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Confused with type definition

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