Just realised there is no Julia soluton to this on Code golf code golf - 1, 2, Fizz, 4, Buzz - Code Golf Stack Exchange

clever, I had tried \circ with println and max but then required another pair (,)

Getting closer! 60 bytes/chars 1:100 .|>x->println(max("$x","Fizz"^(x%3<1)*"Buzz"^(x%5<1))) Edit: sorry haven’t seen the post above with this same solution

Is there some hidden Unicode character to replace the max function call?

Not that I am able to find, interestingly learning a lot about Julia trying to solve this though so its not all for naught

this could be the one if only we could find a way of broadcasting "$x" without string for now is 63 bytes/chars N=1:100;@.println(max(string(N),"Fizz"^(N%3<1)*"Buzz"^(N%5<1)))

Some remarks/observations My suspicion is "$x" is used. Defining the exponents for the strings outside the primary call saves parentheses but then adds characters to insert: i.e. f=x%3<1 is the same length as (x%3<1) but then need to use;. Using the ternary operator a ? b : c certainly takes up…

some other observations: $x needs max and we probably already have the best solution with that idea 0:99 is appealing but I don’t see a way of using it neither. This could be a false friend though, as we’re looking to remove just one byte/char and that blank space after 100 is the obvious targe…

Those two solutions are neat. Searching around for tips for code golfing in Julia, on the Code Golf StackExchange came across discussion for this problem. From the discussion it appears there is a 60char/bye solution using repr and there is a 59char/byte solution using "$x".

another whacky one (65) 1:100 .|>x->println(max("$x",join(("Fizz","Buzz")[x.%[3,5].<1])))

Code-golfing FizzBuzz

General Usage

Max_Beez February 28, 2023, 2:16pm 38

Can shorten this one down to 61
x=1:100;@.println(max(repr(x),"Fizz"^(x%3<1)*"Buzz"^(x%5<1)))

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Code-golfing FizzBuzz

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