What I am trying to get is all the possible values given an array [0, 1, 2] and a number n. The result for n=3 would be: [0,0,0] [0,0,1], [0,0,2] [0,1,0] ... [2,2,2] So basically all the numbers in base 3 given as separate elements in an array. I have been trying to get this output by using Base.…

Here’s how to do it with Iterators.product: N = 3 reverse.(Iterators.product(fill(0:N-1,N)...))[:]

Cleanest way to generate all combinations of n arrays

bennedich January 26, 2019, 3:30pm 6

N = 3
lpad.(string.(0:N^N-1;base=N),N,'0').|>s->Int.(collect(s).-48)

Not the most efficient

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