I Often have an expression t = :(y = f(:x)) I want to examine the head of the RHS, I can do this by looking at rhs = t.args[2] rhs.head ... Unfortunately, if you have t = :(y = :x)) then rhs is a QuoteNode and I get the error type QuoteNode has no field head. I feel like I’ve seen solutions t…

Check head of an expression

simeonschaub October 23, 2020, 7:22am 2

I think you are looking for Meta.isexpr.

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