With this code I get the desired heatmap. using Plots dataMatrix=rand(40,10) heatmap(dataMatrix,levels=10,colorbar=false) But I would like to achieve the image of the heatmap with cluster, as shown in the figure: [clustering visualized with the heatmap] How to achieve it?

I try to reproduce the example in R from this site: Matrix data and Patterns in rows and columns This has been the progress. Welcome the comments, criticisms and improvements !!: #https://bookdown.org/rdpeng/exdata/dimension-reduction.html#matrix-data using Plots using StatsBase using Clusteri…

Haven’t looked at this in detail, but I don’t really understand the need for RCall here? It looks to me like everything up to and including the loop can be replaced by: using Distributions dataMatrix = rand(Normal(), 40, 10) dataMatrix .+= (repeat([0, 3], inner = 5) * rand(Bernoulli(), 40)')'

You can draw the lines as usual using plot(xs, ys) where xs and ys are vectors of x and y coordinates. Use NaNs to break the lines into disjoint pieces.

I used RCall to Generate identical random numbers in R and Julia

Could you give me an example? How to get the graph: [clustering visualized with the heatmap]

I assumed you had a method to calculate the clustering.

Would it be possible to achieve the same results without using RCall? That julia generates a matrix equal to the one generated with RCall! julia> dataMatrix = rand(Normal(), 40, 10) 40×10 Array{Float64,2}: 0.827701 0.720837 -0.394599 0.946286 -0.161712 -0.150407 0.653404 -0.292532 …

It depends on what you mean by “same results” - as you say using Distributions rand(Normal(), 40, 10) in Julia is equivalent to matrix(rnorm(400), nrow = 40)) in that it produces a 40x10 matrix of random numbers, drawn from a standard normal distribution. Of course the numbers won’t exactly be t…

Can be visualized clustering with the heatmap()?

General Usage

HerAdri November 12, 2020, 12:52pm 6

Could you give me an example? How to get the graph:

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Can be visualized clustering with the heatmap()?

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