Hello, I have a Julia function that accepts a sparse matrix and some parameters, and returns two sparse matrices as a result. I know that there is a Pycall, but I don’t want to call an active instance of installed Julia, I want to call a compiled extension similar to how it is possible to have C e…

This is what you want: https://julialang.github.io/PackageCompiler.jl/stable/libs.html#libraries You want to create a C-callable function that will be compiled into a shared library. Once you have that, you can load the library into python and call the function just as you would for any C shared…

Do you have a toy example of how this would work? Also how do I combine Julia sparse matrices, numpy sparse matrices and C?

[image] Darel: I know that there is a Pycall, but I don’t want to call an active instance of installed Julia, I want to call a compiled extension similar to how it is possible to have C extensions for Python Why don’t you want to use PyCall? Or in the case pyjulia (a related package). PyCall …

[image] Darel: Do you have a toy example of how this would work? In the docs, there is a link to here: [image] GitHub - simonbyrne/libcg Contribute to simonbyrne/libcg development by creating an account on GitHub.

Because I want to create a fast module for Python. It is not feasible to ask user to install Julia to use your package. So I want to get a binary or C version of what my function does in Julia, so I can call it from Python.

[image] Darel: Because I want to create a fast module for Python. Creating a C-callable function and using PkgCompiler might be the best option. One advantage of supplying a dynamically linkable library is that people are used them; it won’t scare them away. But, it’s not a lean library. It s…

Call compiled Julia function from Python

New to Julia

Darel November 29, 2021, 9:04pm 7

Yes, I saw this repo, but this is neither toyish nor end-to-end. I was hoping that there is a tutorial of some kind.

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Call compiled Julia function from Python

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