I hear you, yes. subpieces of the algorithm might not be invertibles. But what if the global algorithm is, indeed, invertible ? I mean, f(a,b) = (a+b, exp(a+2b)) is invertible, and you could get more creative.
I hear you, yes. subpieces of the algorithm might not be invertibles. But what if the global algorithm is, indeed, invertible ? I mean, f(a,b) = (a+b, exp(a+2b)) is invertible, and you could get more creative.