Consider this: using ForwardDiff function f!(F, x) F[1] = (x[1]+3)*(x[2]^3-7)+18 F[2] = sin(x[2]*exp(x[1])-1) return F end F = Array{Float64}(undef, 2) x = [1, 1] Now let’s compute the Jacobian. The documentation , says: ForwardDiff.jacobian(f!, y::AbstractArray, x::AbstractArray, c…

julia> ForwardDiff.jacobian(f!, F, x) 2×2 Matrix{Float64}: -6.0 12.0 -0.399455 -0.399455 The documentaiton said ForwardDiff.jacobian(..), not ForwardDiff.jacobian!(...).

A bug in ForwardDiff?

General Usage

amrods May 7, 2021, 3:45am 4

Didn’t see that !!!, I guess it’s time for me to take a break…

How to implement AD for this function?

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A bug in ForwardDiff?

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